4x^2-9x-19=0

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Solution for 4x^2-9x-19=0 equation: 



4x^2-9x-19=0

a = 4; b = -9; c = -19;
Δ = b2-4ac
Δ = -92-4·4·(-19)
Δ = 385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{385}}{2*4}=\frac{9-\sqrt{385}}{8}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{385}}{2*4}=\frac{9+\sqrt{385}}{8}
$

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